The math optional, made finite. Daily Practice

Curl: definition, physical meaning, computation

At a Glance

Why This Chapter Matters

All four appearances of this atom are classified easy — this is guaranteed-mark territory. Every question follows an identical two-step pattern: set each component of ×F\nabla \times \vec F to zero to find unknown parameters, then integrate to recover the scalar potential. The 2017 question adds the minor twist of expressing the divergence in cylindrical coordinates (but since divergence is a scalar invariant, the value is just the Cartesian answer). Investing 15 minutes to internalize the curl formula and the potential-recovery algorithm pays off on four separate years.

Minimum Theory

Curl. For F=Pi^+Qj^+Rk^\vec F = P\hat i + Q\hat j + R\hat k: ×F=(RyQz)i^(RxPz)j^+(QxPy)k^.\nabla \times \vec F = (R_y - Q_z)\hat i - (R_x - P_z)\hat j + (Q_x - P_y)\hat k. Remembered as the 3×33\times3 determinant with rows (i^,j^,k^)(\hat i, \hat j, \hat k), (x,y,z)(\partial_x, \partial_y, \partial_z), (P,Q,R)(P, Q, R).

Irrotational field. ×F=0\nabla \times \vec F = \vec 0 (all three components vanish). This is the necessary and sufficient condition (on a simply connected domain) for the existence of a scalar potential ϕ\phi with F=ϕ\vec F = \nabla\phi.

Potential recovery. Given ϕ=F=(P,Q,R)\nabla\phi = \vec F = (P,Q,R):

  1. Integrate ϕx=P\phi_x = P with respect to xxϕ=Pdx+g(y,z)\phi = \int P\,dx + g(y,z).
  2. Differentiate w.r.t. yy and match QQ → determine gyg_y, integrate → g=()dy+h(z)g = \int(\cdots)\,dy + h(z).
  3. Differentiate w.r.t. zz and match RR → determine h(z)h'(z), integrate.

Curl formula (left) and circulation-density interpretation (right): \nabla\times\vec F = \vec 0 (irrotational) implies \vec F = \nabla\phi (conservative).

Question Archetypes

ArchetypeRecognition cue
irrotational-potential”Verify F\vec F is irrotational; find scalar potential ϕ\phi.“
find-params-irrotational”For what values of a,b,ca,b,c is V\vec V irrotational?“

irrotational-potential (2 questions; 2015, 2022)

Recognition Cues

Solution Template

  1. Compute curl components. Three partial-derivative differences: (RyQz)(R_y-Q_z), (PzRx)(P_z-R_x), (QxPy)(Q_x-P_y). Show each is 0.
  2. Integrate ϕx=P\phi_x = P w.r.t. xx: ϕ=Pdx+g(y,z)\phi = \int P\,dx + g(y,z).
  3. Match ϕy=Q\phi_y = Q: differentiate the result w.r.t. yy; solve for gyg_y; integrate to get gg.
  4. Match ϕz=R\phi_z = R: differentiate w.r.t. zz; solve for h(z)h'(z); integrate.
  5. State ϕ\phi with arbitrary constant CC.

Worked Example(s)

2022 Paper 1, 2022-P1-Q5e (10 marks)

Show A=(6xy+z3)i^+(3x2z)j^+(3xz2y)k^\vec A = (6xy+z^3)\hat i + (3x^2-z)\hat j + (3xz^2-y)\hat k is irrotational; find ϕ\phi.

Curl:

Potential:

ϕ=3x2y+xz3yz+C.\boxed{\phi = 3x^2y + xz^3 - yz + C.}


2015 Paper 1, 2015-P1-Q7c (12 marks)

Verify F=(x2+xy2)i^+(y2+x2y)j^\vec F = (x^2+xy^2)\hat i + (y^2+x^2y)\hat j is irrotational; find scalar potential.

2D field (no zz-component, no zz-dependence): only the k^\hat k curl component matters.

k^\hat k: x(y2+x2y)y(x2+xy2)=2xy2xy=0\partial_x(y^2+x^2y) - \partial_y(x^2+xy^2) = 2xy - 2xy = 0 ✓. Irrotational.

Potential:

ϕ=x33+x2y22+y33+C.\boxed{\phi = \frac{x^3}{3} + \frac{x^2y^2}{2} + \frac{y^3}{3} + C.}

Common Traps


find-params-irrotational (2 questions; 2017, 2020)

Recognition Cues

Solution Template

  1. Write the three curl components as functions of a,b,ca,b,c.
  2. Set each to zero to get 3 equations.
  3. Solve (usually one equation per parameter).
  4. State the potential by integrating the field with the found parameters.

Worked Example(s)

2020 Paper 1, 2020-P1-Q5c (10 marks)

Find a,b,ca,b,c for V=(4x3y+az)i^+(bx+3y+5z)j^+(4x+cy+3z)k^\vec V = (-4x-3y+az)\hat i + (bx+3y+5z)\hat j + (4x+cy+3z)\hat k to be irrotational.

Curl components:

a=4,  b=3,  c=5.\boxed{a=4,\; b=-3,\; c=5.}

Potential: with these values, integrate as in the template: ϕ=2x2+32y2+32z23xy+4xz+5yz+C.\phi = -2x^2 + \tfrac{3}{2}y^2 + \tfrac{3}{2}z^2 - 3xy + 4xz + 5yz + C.


2017 Paper 1, 2017-P1-Q5d (10 marks)

Find a,b,ca,b,c for V=(x+y+az)i^+(bx+2yz)j^+(x+cy+2z)k^\vec V = (x+y+az)\hat i + (bx+2y-z)\hat j + (-x+cy+2z)\hat k to be irrotational; find the divergence in cylindrical coordinates.

Curl:

a=1,  b=1,  c=1.\boxed{a=-1,\; b=1,\; c=-1.}

Divergence in cylindrical coordinates. The divergence V\nabla \cdot \vec V is a scalar invariant — its value is independent of the coordinate system. In Cartesian: V=x(x+yz)+y(x+2yz)+z(xy+2z)=1+2+2=5.\nabla \cdot \vec V = \partial_x(x+y-z) + \partial_y(x+2y-z) + \partial_z(-x-y+2z) = 1+2+2 = 5. In cylindrical coordinates, the divergence formula gives the same constant 55.

Common Traps

Marks-Aware Writing

10-mark irrotational + potential: Show three curl components vanish (3 lines). Then three integration steps for the potential (3 lines). State the answer. Total ~7 lines.

10-mark find-params + divergence: Three one-line equations from curl = 0 (immediate). State the divergence (one line) and note coordinate invariance (one sentence).

Practice Set

We've mapped all 13 years of this exam. Get new chapters, tools, and solutions as we release them — free.