Frequency: 9 sub-parts across 9 of 13 years (2013, 2015, 2016, 2017, 2018, 2021, 2022, 2023, 2025)
Priority tier: T1
Marks (count): 10 (3), 15 (3), 20 (3)
Average solve time: ~15 min
Difficulty mix: hard 4, medium 3, easy 2
Section: B | Dominant type: derivation
Why This Chapter Matters
Lagrange’s equations appear in 9 of the last 13 years, with an even split across 10-, 15-, and 20-mark questions. The method is systematic: once you write down T and V, the rest is calculus. UPSC favours four physical setups — rolling bodies, pulley systems, central-force orbits, and coupled oscillators — and one abstract setup (a given Lagrangian to differentiate). Mastering the procedure means these 9 appearances become largely mechanical.
Minimum Theory
Euler–Lagrange equations. For a system with generalised coordinates q1,…,qn and Lagrangian L=T−V:
dtd∂q˙k∂L−∂qk∂L=Qk,k=1,…,n,
where Qk is the generalised force for qk (zero if no non-conservative forces, or if V is complete). For a force F applied at point r: Qk=F⋅∂r/∂qk.
Steps to form the Lagrangian:
Choose generalised coordinates; apply any holonomic constraints to reduce the number of DOFs.
Write T (kinetic energy) in terms of q˙k. For rigid bodies: T=21Ipivotθ˙2 (rotation about fixed axis) or T=21mvCM2+21ICMθ˙2 (König’s theorem).
Write V in terms of qk.
Form L=T−V and differentiate.
Normal modes. For a system near equilibrium, linearise T and V to get T=21q˙TMq˙ and V=21qTKq. Normal-mode frequencies satisfy det(K−ω2M)=0.
Question Archetypes
Three patterns cover all Lagrange’s equations questions.
Hoop of radius r rolls without slipping down incline of length l, angle ϕ. Write Lagrange’s equations and find velocity at bottom.
Rolling constraint:s˙=rψ˙ (holonomic; reduces to one DOF s). Hoop: I=Mr2, so total T=21Ms˙2+21(Mr2)(s˙/r)2=Ms˙2.
L=Ms˙2−Mg(l−s)sinϕ.
EL: 2Ms¨=Mgsinϕ⇒s¨=21gsinϕ.
Kinematics (v2=2al from rest): v2=2⋅21gsinϕ⋅l=glsinϕ.
v=glsinϕ.
(Independent of M and r — good sanity check.)
2022 Paper 2, 2022-P2-Q5d (10 marks)
Particle under central force F=−k/r2. Find Lagrangian and equations of motion.
In polar (r,θ): T=21m(r˙2+r2θ˙2), V=−k/r.
L=21m(r˙2+r2θ˙2)+rk.
EL for r: mr¨=mrθ˙2−k/r2. EL for θ: dtd(mr2θ˙)=0 (θ cyclic — angular momentum conserved).
mr¨=mrθ˙2−r2k,mr2θ˙=const.
2025 Paper 2, 2025-P2-Q5d (10 marks)
Bead on frictionless cycloid x=a(θ−sinθ), y=a(1+cosθ). Find L; show EOM is u¨+(g/4a)u=0, u=cos(θ/2).
Speed.x˙2+y˙2=a2θ˙2⋅2(1−cosθ)=4a2sin2(θ/2)θ˙2. Using 1−cosθ=2sin2(θ/2).
T=2ma2sin2(2θ)θ˙2,V=mga(1+cosθ)=2mgacos2(2θ).
L=2ma2sin2(2θ)θ˙2−2mgacos2(2θ).
EL equation (after dividing by 2masin(θ/2)):
2asin2θθ¨+acos2θθ˙2−gcos2θ=0.
With u=cos(θ/2): u˙=−21sin(θ/2)θ˙, u¨=−21sin(θ/2)θ¨−41cos(θ/2)θ˙2. Multiplying the EL equation by −41: au¨+4gu=0.
dt2d2u+4agu=0(SHM, period 4πa/g).
2018 Paper 2, 2018-P2-Q6c (20 marks)
L=21m(ax˙2+2bx˙y˙+cy˙2)−21k(ax2+2bxy+cy2), b2=ac. Write EL equations; identify system.
With M=(abbc), both T and V share the same matrix: mMr¨=−kMr. Since detM=ac−b2=0, multiply by M−1:
mx¨+kx=0,my¨+ky=0.
Two independent SHMs with ω=k/m.
2017 Paper 2, 2017-P2-Q6c (20 marks)
Two uniform rods AB, AC (each mass m, length 2a) hinged at A, moving on a horizontal plane. Prove T=m[ξ˙2+η˙2+(31+sin2ϕ)a2θ˙2+(31+cos2ϕ)a2ϕ˙2]; derive Lagrange’s equations if force (X,Y) acts at A.
König’s theorem for each rod (translation of Gi + rotation about Gi, IGi=ma2/3). Express the hinge A through the system CM: ξ=xA+acosϕcosθ, etc. After substituting and collecting trig identities (cos(θ±ϕ) sums), cross terms cancel giving the stated T.
Generalised forces from (X,Y) at A: Qξ=X, Qη=Y, Qθ=acosϕ(Xsinθ−Ycosθ), Qϕ=asinϕ(Xcosθ+Ysinθ).
EL equations:2mξ¨=X,2mη¨=Y,32ma2[(1+3sin2ϕ)θ¨+3sin2ϕθ˙ϕ˙]=Qθ,32ma2[(1+3cos2ϕ)ϕ¨−23sin2ϕ(θ˙2+ϕ˙2)]=Qϕ.
Common Traps
Rolling constraint first. For the hoop: I=Mr2 makes total KE =Ms˙2 (double the translational). A disc (I=21Mr2) gives a=32gsinϕ; a sphere (I=52Mr2) gives a=75gsinϕ. Don’t mix them.
For the given-Lagrangian problem (2018): the condition b2=ac makes M invertible — don’t attempt a generalised eigenvalue problem; the normal modes are just x and y themselves.
For the hinged-rods problem (2017): the force acts at A, not at the CM — compute Qk=F⋅∂rA/∂qk.
For the cycloid (2025): use 1−cosθ=2sin2(θ/2) to simplify T, then recognise the EL equation can be written in terms of u=cos(θ/2) — the tautochrone.
normal-modes (2 question(s); 2013, 2023)
Recognition Cues
“Show that the periods are 2π/n where n2=…” — multiple natural frequencies required.
Two coupled masses or rods; small-angle linearisation.
Or: given L=21m(x˙2+y˙2)−21m(ω12x2+ω22y2)+kxy; find a rotation that decouples it.
Solution Template
Choose generalised coordinates; write full (nonlinear) T and V.
Linearise: cos(θ1−θ2)≈1, cosθ≈1−θ2/2; keep only quadratic terms.
Read off mass matrix M and stiffness matrix K from T=21q˙TMq˙, V=21qTKq.
Solve det(K−n2M)=0 for the normal frequencies. Use the quadratic formula; factor the discriminant.
Check: all n2>0 (stable equilibrium).
Worked Example(s)
2013 Paper 2, 2013-P2-Q8a (15 marks)
Two equal rods AB, BC (mass m, length l) jointed at B, suspended from A. Show n2=(3±6/7)g/l.
Generalised coordinates:θ1 (angle of AB), θ2 (angle of BC).
Full T (König for BC: translation of G2 + spin θ˙2 about G2):
T=32ml2θ˙12+6ml2θ˙22+2ml2cos(θ1−θ2)θ˙1θ˙2.
det(K−n2M)=0 expands to 7l2n4−42gln2+27g2=0. Discriminant =127gl:
n2=14l242gl±127gl=lg(3±76).
n2=(3±76)lg;T=n2π.
2023 Paper 2, 2023-P2-Q6c (20 marks)
L=21m(x˙2+y˙2)−21m(ω12x2+ω22y2)+kxy. Find θ so that the (q1,q2) Lagrangian has no q1q2 cross term. Find the Lagrange equations independent of θ.
Rotation invariance of T:x˙2+y˙2=q˙12+q˙22 (orthogonal rotation).
Cross-term coefficient in L after rotation:
21m(ω12−ω22)sin2θ+kcos2θ=0⟹tan2θ=m(ω22−ω12)2k.
θ=21arctanm(ω22−ω12)2k.
Normal frequencies (eigenvalues of the potential matrix, independent of θ):
Ω1,22=2ω12+ω22±(2ω12−ω22)2+m2k2.
EL equations:q¨1+Ω12q1=0, q¨2+Ω22q2=0.
Common Traps
Rod AB rotates about fixed pivot A: use IA=ml2/3. Rod BC rotates about its own (moving) CG: use IG2=ml2/12 plus translational KE. Confusing these gives wrong M.
Discriminant 1008=127 — factor 1008=144×7 to see the simplification; otherwise the answer looks wrong.
In the 2023 problem: K=kM leads to a degenerate generalised eigenvalue problem when the matrices share the same eigenvectors — but here the cross-term rotation is needed first.
gauge-lagrangian (1 question(s); 2015)
Recognition Cues
A Lagrangian with explicit e−αt time dependence given; find an equivalent time-independent form.
“Find an equivalent Lagrangian not explicitly dependent on time.”
Solution Template
Add dtdF for F(q,t) chosen to absorb the time-dependent terms. The key identity: dtd(−αbq2e−αt/2)=−αbqq˙e−αt+α2bq2e−αt/2, which cancels both offending terms in L.
Worked Example(s)
2015 Paper 2, 2015-P2-Q7c-ii (10 marks)
Starting from L=2αq˙2+αbqq˙e−αt−2bα2q2e−αt−2kq2, find an equivalent time-independent Lagrangian.
Add dtdF with F=−2αbq2e−αt:
dtdF=−αbqq˙e−αt+2α2bq2e−αt.
Both e−αt terms in L cancel:
L′=L+dtdF=2αq˙2−2kq2.
L′=2αq˙2−2kq2(SHM with mass α, spring constant k).
Common Traps
The time-dependent parts are “gauge artifacts” — the underlying dynamics is SHM with frequency k/α, independent of b.
Spot F by matching: dF/dt must reproduce the unwanted terms with opposite signs. Here both the qq˙e−αt and q2e−αt terms are cancelled by a single F.
Marks-Aware Writing
10-mark questions (2021, 2022, 2025-Q5d): Write T and V (two lines), form L, write EL for the single coordinate, state the result. For the given-L variant (2022): just differentiate and identify.
15-mark questions (2013, 2016, 2021): State the constraint (holonomic); write T with moment of inertia used explicitly; form L; EL equation in one line; solve by kinematics or energy. For normal modes (2013): show both linearised T and V matrices before writing the characteristic equation.
20-mark questions (2017, 2018, 2023): Full derivation expected. For 2017: prove the T formula step by step (König’s theorem, write each rod’s KE, collect terms), state all four generalised forces, write all four EL equations. For 2023: show the rotation, compute the cross-term coefficient, set to zero, state Ω1,2.
Practice Set
Year
Paper/Q
Marks
Archetype
One-line hint
2025
P2-Q5d
10
lagrange-eom
T=2ma2sin2(θ/2)θ˙2; u=cos(θ/2) reduces EL to u¨+(g/4a)u=0
2023
P2-Q6c
20
normal-modes
Rotation makes potential diagonal; tan2θ=2k/[m(ω22−ω12)]; Ω1,22 are eigenvalues