The math optional, made finite. Daily Practice

Vortex motion; circulation

At a Glance

Why This Chapter Matters

Vortex motion is the highest-frequency T3 atom in Paper 2, appearing in Section B at 10–20 marks. The three most common question types are: (a) compute vorticity and circulation for a given velocity field; (b) show a flow is irrotational, find its streamlines, and identify a velocity potential; and (c) prove vortex lines are orthogonal to streamlines under a given condition. All three reduce to computing ×q\nabla\times\mathbf{q}, q\nabla\cdot\mathbf{q}, and solving simple differential equations. The key identity: any gradient field is curl-free; the key insight for (b): irrotational + incompressible = potential flow.

Minimum Theory

Point vortex: concentric circular streamlines and velocity potential \phi=\lambda\theta

Vorticity. The vorticity of a velocity field q=(u,v,w)\mathbf{q}=(u,v,w) is ω=×q\boldsymbol{\omega}=\nabla\times\mathbf{q}. The flow is irrotational if ω=0\boldsymbol{\omega}=\mathbf{0} everywhere.

Circulation. The circulation around a closed curve CC is Γ=Cqdr\Gamma=\oint_C\mathbf{q}\cdot d\mathbf{r}. By Stokes’ theorem, Γ=S(×q)dS\Gamma=\iint_S(\nabla\times\mathbf{q})\cdot d\mathbf{S}. If ×q=0\nabla\times\mathbf{q}=\mathbf{0} on the enclosed surface, then Γ=0\Gamma=0.

Potential flow. If ×q=0\nabla\times\mathbf{q}=\mathbf{0} on a simply-connected region, there exists a velocity potential ϕ\phi with q=ϕ\mathbf{q}=\nabla\phi.

Incompressibility. q=0\nabla\cdot\mathbf{q}=0 (solenoidal flow). Required for the equation of continuity.

Point vortex. The fundamental irrotational, incompressible 2D flow with non-zero circulation around the origin: q=λ(y,x)x2+y2=λrθ^.\mathbf{q}=\frac{\lambda(-y,x)}{x^2+y^2}=\frac{\lambda}{r}\hat{\boldsymbol{\theta}}. Streamlines: concentric circles x2+y2=constx^2+y^2=\text{const}. Velocity potential: ϕ=λθ=λarctan(y/x)\phi=\lambda\theta=\lambda\arctan(y/x) (multi-valued; circulation =2πλ=2\pi\lambda). Irrotational everywhere except at the origin singularity.

Gradient split. If q=q1+f\mathbf{q}=\mathbf{q}_1+\nabla f (polynomial part plus a gradient), then ×q=×q1\nabla\times\mathbf{q}=\nabla\times\mathbf{q}_1 (gradient is curl-free). This reduces vorticity calculations to the polynomial part only.

Question Archetypes

ArchetypeRecognition
vorticity-circulationGiven q\mathbf{q}; compute ×q\nabla\times\mathbf{q}; find circulation via Stokes
potential-stream-functionShow q\mathbf{q} is incompressible; find streamlines; check irrotational; find ϕ\phi
vortex-stream-orthogonalityProve Vω=0\mathbf{V}\cdot\boldsymbol{\omega}=0 under a given condition

vorticity-circulation (1 question(s); 2016)

Worked Example

2016 Paper 2, 2016-P2-Q5b (10 marks)

q=(z2x/r,  2y3z2y/r,  x3y2z/r)\mathbf{q}=(z-2x/r,\;2y-3z-2y/r,\;x-3y-2z/r) where r2=x2+y2+z2r^2=x^2+y^2+z^2. Find vorticity; find circulation around x2+y2=9x^2+y^2=9, z=0z=0.

Split: q=(z,2y3z,x3y)q12r/r=(2r)\mathbf{q}=\underbrace{(z,2y-3z,x-3y)}_{\mathbf{q}_1}-\underbrace{2\mathbf{r}/r}_{=\nabla(2r)}.

Since 2r/r=(2r)2\mathbf{r}/r=\nabla(2r) is a gradient: ×q=×q1\nabla\times\mathbf{q}=\nabla\times\mathbf{q}_1.

Vorticity of q1\mathbf{q}_1: ω=(y(x3y)z(2y3z),  z(z)x(x3y),  x(2y3z)y(z))\boldsymbol{\omega}=\bigl(\partial_y(x-3y)-\partial_z(2y-3z),\;\partial_z(z)-\partial_x(x-3y),\;\partial_x(2y-3z)-\partial_y(z)\bigr) =(3(3),  11,  00)=0.=(-3-(-3),\;1-1,\;0-0)=\mathbf{0}.

Circulation: Γ=D(×q)k^dS=0\Gamma=\iint_{D}(\nabla\times\mathbf{q})\cdot\hat{k}\,dS=0 by Stokes (zero curl on the disc).

ω=0  (irrotational);Γ=0.\boxed{\boldsymbol{\omega}=\mathbf{0}\;\text{(irrotational)};\quad\Gamma=0.}

Recognition pattern: when the velocity field splits as “polynomial + f(r)f(\mathbf{r})”, check if f(r)f(\mathbf{r}) is a gradient; radial fields f(r)rf(r)\mathbf{r} are gradients of f(r)dr\int f(r)\,dr.

potential-stream-function (1 question(s); 2021)

Worked Example

2021 Paper 2, 2021-P2-Q7c (20 marks)

q=λ(y,x)/(x2+y2)\mathbf{q}=\lambda(-y,x)/(x^2+y^2). Show incompressible, find streamlines, check irrotational, find velocity potential.

Incompressibility: x(λy/(x2+y2))+y(λx/(x2+y2))=2λxy/(x2+y2)22λxy/(x2+y2)2=0\partial_x(-\lambda y/(x^2+y^2))+\partial_y(\lambda x/(x^2+y^2))=2\lambda xy/(x^2+y^2)^2-2\lambda xy/(x^2+y^2)^2=0. ✓

Streamlines: dx/(y)=dy/xdx/(-y)=dy/x (cancel λ/(x2+y2)\lambda/(x^2+y^2)). Cross-multiply: xdx+ydy=0d(x2+y2)=0x\,dx+y\,dy=0\Rightarrow d(x^2+y^2)=0. Streamlines: concentric circles x2+y2=cx^2+y^2=c.

Irrotational: ωz=xvyu=λ(y2x2)/(x2+y2)2λ(y2x2)/(x2+y2)2=0\omega_z=\partial_x v-\partial_y u=\lambda(y^2-x^2)/(x^2+y^2)^2-\lambda(y^2-x^2)/(x^2+y^2)^2=0. (Away from origin.) ✓

Velocity potential: ϕ/x=λy/(x2+y2)=x(λarctan(y/x))\partial\phi/\partial x=-\lambda y/(x^2+y^2)=\partial_x(\lambda\arctan(y/x)). So ϕ=λarctan(y/x)=λθ\phi=\lambda\arctan(y/x)=\lambda\theta.

Streamlines: x2+y2=c;ϕ=λθ=λarctan(y/x).\boxed{\text{Streamlines: }x^2+y^2=c;\quad\phi=\lambda\theta=\lambda\arctan(y/x).}

Note: ϕ\phi is multi-valued (jumps by 2πλ2\pi\lambda around the origin). The flow is the classical point vortex — irrotational everywhere except the singular origin, with circulation Γ=2πλ\Gamma=2\pi\lambda.

vortex-stream-orthogonality (covered in T2/neighbouring atoms)

The 2013 question (P2-MF-09 primary) asks to prove vortex lines are orthogonal to streamlines when V=μϕ\mathbf{V}=\mu\nabla\phi. Key: Vω=μϕ(μ×ϕ)=0\mathbf{V}\cdot\boldsymbol{\omega}=\mu\nabla\phi\cdot(\nabla\mu\times\nabla\phi)=0 (scalar triple product with a repeated factor). This is the pure curl-gradient orthogonality identity.

Common Traps

Marks-Aware Writing

For vorticity + circulation (10 marks): split the field, identify the gradient part, compute ×q1\nabla\times\mathbf{q}_1 component by component (show all three components vanish), then invoke Stokes. Four visible steps.

For the potential-flow question (20 marks): each of the four sub-tasks (incompressible, streamlines, irrotational, potential) earns separate marks. The streamlines step needs the ODE dx/u=dy/vdx/u=dy/v written out and solved. The potential step needs both partial derivatives of ϕ\phi verified.

Practice Set

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