CSAT Solved Papers/ 2021/Q45

2021 CSAT — Q45

Quant Data interpretation 2.5 marks Medium

Consider the following Table:

Player	Runs scored in the First Innings	Balls faced in the First Innings	Runs scored in the Second Innings	Balls faced in the Second Innings
A	$61$	$99$	$14$	$76$
B	$05$	$12$	$50$	$85$
C	$15$	$75$	$20$	$50$
D	$13$	$55$	$12$	$50$

Who is the fastest run scorer in the Test Match?

A A
B B Answer
C C
D D

Worked rationale

“Fastest run scorer” means the highest strike rate $=\dfrac{\text{total runs}}{\text{total balls}}$ across both innings.

Player	total runs	total balls	runs per ball
A	$61+14 = 75$	$99+76 = 175$	$75/175 = 0.43$
B	$5+50 = 55$	$12+85 = 97$	$55/97 = 0.57$
C	$15+20 = 35$	$75+50 = 125$	$35/125 = 0.28$
D	$13+12 = 25$	$55+50 = 105$	$25/105 = 0.24$

$B$ has the highest runs-per-ball ( $\approx 0.57$ ).

Answer: (b) B.

Why the other options miss

A

ranks the wrong quantity: goes by total runs ( $75$ , the most) instead of run rate.
C

an arithmetic slip: forms the rate from one innings only, or divides runs and balls the wrong way round.
D

wrong measure of “fastest”: judges it by fewest balls faced rather than runs per ball.

Specialist insight

“Fastest” in cricket is a rate, not a total — so the only correct comparison is runs $\div$ balls over the whole match. Sum each player’s two innings first, then compare four single fractions. The deliberate lure is $A$ , the top run-getter ( $75$ ) but a pedestrian rate ( $0.43$ ); the winner $B$ scores fewer runs yet fastest ( $0.57$ ). When a DI item says “fastest / cheapest / most efficient,” reach for the ratio, never the raw column.

The trap, in one line

Strike rate $=$ runs $/$ balls; $B = 55/97 \approx 0.57$ is highest, beating top-scorer $A$ $\Rightarrow$ (b).

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