CSAT Solved Papers/ 2021/Q78

2021 CSAT — Q78

Quant Arithmetic & numeracy 2.5 marks Easy

If the price of an article is decreased by 20%20\% and then the new price is increased by 25%25\%, then what is the net change in the price?

  1. A 0% Answer
  2. B 5% increase
  3. C 5% decrease
  4. D Cannot be determined due to insufficient data

Worked rationale

Apply the changes as multipliers on the original price:

net multiplier=(10.20)×(1+0.25)=0.80×1.25=1.00.\text{net multiplier} = (1 - 0.20)\times(1 + 0.25) = 0.80 \times 1.25 = 1.00.

The final price equals the original, so the net change is 0%0\%.

Answer: (a) 0%.

Why the other options miss

  • B
    added the percentages: does 20%+25%=+5%-20\% + 25\% = +5\% instead of multiplying the factors.
  • C
    wrong base: applies the 25%25\% rise to the original price, not the reduced one.
  • D
    thought a real price was needed: misses that successive percentages give a fixed multiplier.

Specialist insight

Successive percentage changes multiply, never add — the whole trap is the 20%-20\% then +25%+25\% looking like a net +5%+5\%. The factors 0.8×1.25=10.8\times 1.25 = 1 exactly because 1.25=1/0.81.25 = 1/0.8, so the rise perfectly undoes the fall. You never need a real price: chain the multipliers and read off the net factor. Whenever a fall of a%a\% is followed by a rise of a1a/100%\dfrac{a}{1-a/100}\%, the result is back to the start.

The trap, in one line

0.8×1.25=1.00.8 \times 1.25 = 1.0 (multiply, don't add), so net change =0%= 0\% \Rightarrow (a).

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