CSAT Solved Papers/ 2022/Q37

2022 CSAT — Q37

Quant Data sufficiency 2.5 marks Medium

Consider the Question and two Statements given below in respect of three cities P,QP, Q and RR in a State:

Question: How far is city PP from city QQ?

Statement-1: City QQ is 1818 km from city RR.

Statement-2: City PP is 4343 km from city RR.

Which one of the following is correct in respect of the Question and the Statements?

  1. A Statement-1 alone is sufficient to answer the Question
  2. B Statement-2 alone is sufficient to answer the Question
  3. C Both Statement-1 and Statement-2 are sufficient to answer the Question
  4. D Both Statement-1 and Statement-2 are not sufficient to answer the Question Answer

Worked rationale

We want PQPQ.

Statement-1 alone (QR=18QR = 18): says nothing about PP. Insufficient.

Statement-2 alone (PR=43PR = 43): says nothing about QQ. Insufficient.

Both together (QR=18QR = 18, PR=43PR = 43): the three cities need not be collinear. By the triangle inequality, PQPQ can be anything in the range

4318PQ43+18,i.e.25PQ61,|43 - 18| \le PQ \le 43 + 18,\qquad\text{i.e.}\quad 25 \le PQ \le 61,

so PQPQ is not uniquely determined — e.g. collinear with P,R,QP,R,Q in a line gives PQ=61PQ = 61 or 2525, while a right angle at RR gives PQ=432+18246.6PQ = \sqrt{43^2 + 18^2} \approx 46.6. The answer is not fixed even jointly.

Answer: (d) Both Statement-1 and Statement-2 are not sufficient.

Visual solution

The same solve, worked by hand — read it, then trace it.

Hand-drawn worked solution for UPSC 2022 CSAT Q37 — Data sufficiency
Tap the drawing to open it full size for the fine detail.

Why the other options miss

  • A
    thought it was enough when it wasn’t: thinks one distance from RR locates PP relative to QQ.
  • B
    thought it was enough when it wasn’t: the same overreach using PRPR alone.
  • C
    thought it was enough when it wasn’t: assumes the cities are collinear (so PQ=4318=25PQ = 43 - 18 = 25 or 43+18=6143 + 18 = 61), forcing a value the problem never guarantees.

Specialist insight

The engineered trap is assuming collinearity. Two side-lengths of a triangle fix the third only when the included angle is known; here RR is a shared vertex but the angle PRQ\angle PRQ is free, so PQPQ ranges over [25,61][25, 61]. On distance DS, always ask “are these points forced onto a line?” — if not, two radii from a common point leave the third distance open.

The trap, in one line

QR=18,PR=43QR=18, PR=43 leave PQ[25,61]PQ \in [25, 61] (angle at RR free) — not unique \Rightarrow (d).

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