CSAT Solved Papers/ 2022/Q75

2022 CSAT — Q75

Quant Logical & quantitative reasoning 2.5 marks Medium

What is the value of XX in the sequence 2, 12, 36, 80, 150, X2,\ 12,\ 36,\ 80,\ 150,\ X?

  1. A 248
  2. B 252 Answer
  3. C 258
  4. D 262

Worked rationale

Test the pattern n2(n+1)n^2(n+1):

122=2,223=12,324=36,425=80,526=150.1^2\cdot 2 = 2,\quad 2^2\cdot 3 = 12,\quad 3^2\cdot 4 = 36,\quad 4^2\cdot 5 = 80,\quad 5^2\cdot 6 = 150.

All five match, so the next term (n=6n = 6) is

627=36×7=252.6^2 \cdot 7 = 36 \times 7 = 252.

Answer: (b) 252.

Why the other options miss

  • A
    an arithmetic slip: extrapolates a difference pattern (+98+98) instead of the formula.
  • C
    wrong formula: uses n(n+1)2n(n+1)^2 or n3+nn^3 + n and mis-evaluates near the true value.
  • D
    an arithmetic slip: adds a wrong constant to 150150 from a misread second-difference.

Specialist insight

The terms 2,12,36,80,1502, 12, 36, 80, 150 are n2(n+1)n^2(n+1) — recognisable because each is n2n^2 times the next integer (12,43,94,165,2561{\cdot}2, 4{\cdot}3, 9{\cdot}4, 16{\cdot}5, 25{\cdot}6). Spotting a clean product form beats chasing differences (10,24,44,7010, 24, 44, 70 — whose own differences are 14,20,2614, 20, 26, a cubic signature). When differences are themselves growing linearly twice over, look for a degree-33 closed form.

The trap, in one line

Terms are n2(n+1)n^2(n+1); next is 627=2526^2\cdot 7 = 252 \Rightarrow (b).

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