CSAT Solved Papers/ 2024/Q45

2024 CSAT — Q45

Quant Number theory 2.5 marks Medium

What is the number of fives used in numbering a 260260-page book?

  1. A 55
  2. B 56 Answer
  3. C 57
  4. D 60

Worked rationale

Count appearances of the digit 55 across 11 to 260260, place by place.

Units place (5\dots5): 5,15,25,,2555, 15, 25, \dots, 255. That is 255510+1=26\frac{255 - 5}{10} + 1 = 26 numbers.

Tens place (5_\dots5\_): the blocks 50505959, 150150159159, 250250259259 each contribute 1010 fives: 10+10+10=3010 + 10 + 10 = 30.

Hundreds place: the hundreds digit ranges over 0,1,20,1,2 only (up to 260260), never 55: 00.

Total =26+30+0=56= 26 + 30 + 0 = 56.

Answer: (b) 56.

Why the other options miss

  • A
    the fence-and-posts miscount: drops one units-place five (e.g. counts the 55255255 run as 2525 by a fencepost slip).
  • C
    off by one: over-counts the tens block (e.g. extends 250250259259 to include a phantom 55 in 260260) or double-counts 255255.
  • D
    missed a case: assumes a clean 66 fives per hundred ×\times … or rounds to ”1010 per 5050,” ignoring that the third hundred stops at 260260, not 299299.

Specialist insight

Digit-frequency questions are won by separating the places and counting each independently — never try to count “numbers containing a 55” (which double-counts 5555, 155155, 255255). Units fives recur every 1010; tens fives come in full blocks of 1010 per hundred only where the range reaches them. The cap at 260260 is the trap: the third hundred yields its tens block (250250259259) but the units run still ends at 255255, and the hundreds digit is never 55. Count 255255 exactly once in each place it legitimately appears.

The trap, in one line

Count fives place-by-place (2626 in units, 3030 in tens, 00 in hundreds), respecting the 260260 cap — total 5656, not "1010 per fifty".

← All 2024 CSAT questions