← 2013 Paper 2

UPSC 2013 Maths Optional Paper 2 Q2a — Step-by-Step Solution

10 marks · Section A

Permutation Groups (S_n): Cycle Decomposition, Sign, A_n · Algebra · asked 2× in 13 yrs · Read the full method →

Question

What are the orders of the following permutations in S10S_{10}?

(1234567891018731054269)and(12345)(67).\begin{pmatrix}1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10\\ 1 & 8 & 7 & 3 & 10 & 5 & 4 & 2 & 6 & 9\end{pmatrix}\quad\text{and}\quad(1\,2\,3\,4\,5)(6\,7).

Technique

Disjoint-cycle decomposition; lcm of cycle lengths is the order.

Solution

Strategy. The order of a permutation equals the lcm of its disjoint-cycle lengths.

Permutation 1

Trace out the cycles by following 1σ(1)σ2(1)1\to\sigma(1)\to\sigma^{2}(1)\to\ldots:

Cycle decomposition: σ=(28)(374)(51096)\sigma=(2\,8)(3\,7\,4)(5\,10\,9\,6) with one fixed point.

Order=lcm(2,3,4)=12.\text{Order}=\operatorname{lcm}(2,3,4)=12.

Permutation 2

τ=(12345)(67)\tau=(1\,2\,3\,4\,5)(6\,7) — a 5-cycle and a 2-cycle, already in disjoint form.

Order=lcm(5,2)=10.\text{Order}=\operatorname{lcm}(5,2)=10.

Final answer

Answer

  Orders: 12 and 10.  \boxed{\;\text{Orders: }12\text{ and }10.\;}
We post more of this — worked solutions, CSAT trap breakdowns, guide chapters — a few times a week on Telegram. Free, no sign-in. Join

This solution is part of the Maths Coverage Map — 13 years, mapped. Get the take-away PDF free.