← 2013 Paper 2
UPSC 2013 Maths Optional Paper 2 Q2a — Step-by-Step Solution
10 marks · Section A
Permutation Groups (S_n): Cycle Decomposition, Sign, A_n · Algebra · asked 2× in 13 yrs · Read the full method →
Question
What are the orders of the following permutations in S10?
(1128374351065748296109)and(12345)(67).
Technique
Disjoint-cycle decomposition; lcm of cycle lengths is the order.
Solution
Strategy. The order of a permutation equals the lcm of its disjoint-cycle lengths.
Permutation 1
Trace out the cycles by following 1→σ(1)→σ2(1)→…:
- 1→1 — fixed point (1-cycle).
- 2→8→2 — 2-cycle (28).
- 3→7→4→3 — 3-cycle (374).
- 5→10→9→6→5 — 4-cycle (51096).
Cycle decomposition: σ=(28)(374)(51096) with one fixed point.
Order=lcm(2,3,4)=12.
Permutation 2
τ=(12345)(67) — a 5-cycle and a 2-cycle, already in disjoint form.
Order=lcm(5,2)=10.
Final answer
Answer
Orders: 12 and 10.