← 2015 Paper 1
UPSC 2015 Maths Optional Paper 1 Q1b — Step-by-Step Solution
10 marks · Section A
Rank of a matrix · Linear Algebra · asked 7× in 13 yrs · Read the full method →
Question
Reduce the following matrix to row echelon form and hence find its rank:
121821513451445717.
Technique
Gaussian elimination producing row echelon form; count non-zero rows.
Solution
Let A denote the given matrix. Apply elementary row operations.
Step 1 — Eliminate column 1 below the pivot
R2→R2−2R1,R3→R3−R1,R4→R4−8R1:
10002−33−153−22−104−33−15.
Step 2 — Eliminate column 2 below the second pivot
Pivot in R2 is −3. Use R3→R3+R2 and R4→R4−5R2:
10002−3003−2004−300.
This is row echelon form.
Step 3 — Read off rank
There are 2 non-zero rows. Hence
Answer
rank(A)=2.