← 2016 Paper 2
UPSC 2016 Maths Optional Paper 2 Q8a — Step-by-Step Solution
20 marks · Section B
Heat equation · PDEs · asked 3× in 13 yrs · Read the full method →
Question
Find the temperature u(x,t) in a bar of silver of length 10 cm and constant cross-section of area 1 cm². Let density ρ=10.6 g/cm³, thermal conductivity K=1.04 cal/(cm sec °C) and specific heat σ=0.056 cal/g °C. The bar is perfectly isolated laterally, with ends kept at 0°C and initial temperature f(x)=sin(0.1πx) °C. Note that u(x,t) follows the heat equation ut=c2uxx, where c2=K/(ρσ).
Technique
Separation of variables for the heat equation with homogeneous Dirichlet ends; eigenfunctions sin(nπx/10) with decay e−c2(nπ/10)2t; the initial condition is the n=1 eigenfunction, so only that single mode survives — no Fourier coefficients to integrate.
Solution
Setup. One-dimensional heat equation on 0≤x≤10:
ut=c2uxx,u(0,t)=u(10,t)=0,u(x,0)=sin(0.1πx),
with c2=ρσK.
Step 1 — Diffusivity
c2=ρσK=10.6×0.0561.04=0.59361.04=1.7520 cm2/s.
Step 2 — Separation of variables (general)
Seeking u=X(x)T(t) with u(0)=u(L)=0, L=10, gives the eigenfunctions and modes
Xn(x)=sinLnπx=sin10nπx,Tn(t)=e−c2(nπ/L)2t,
so the general solution is the Fourier sine series
u(x,t)=n=1∑∞Bnsin10nπxe−c2(nπ/10)2t.
Step 3 — Match the initial condition
The initial profile is f(x)=sin(0.1πx)=sin10πx — exactly the first eigenfunction (n=1). Hence B1=1 and all other Bn=0; no series summation is needed.
Step 4 — Temperature
With n=1, the decay rate is
c2(10π)2=1.7520×100π2=1.7520×0.098696=0.17292 s−1.
Answer
u(x,t)=sin(10πx)e−0.1729t=sin(0.1πx)e−c2(π/10)2t,c2=1.752 cm2/s.