← 2017 Paper 1

UPSC 2017 Maths Optional Paper 1 Q5a — Step-by-Step Solution

10 marks · Section B

Formulation of differential equations · ODEs · asked 2× in 13 yrs · Read the full method →

Question

Find the differential equation representing all the circles in the xx-yy plane.

Technique

A circle has 3 parameters \Rightarrow differentiate three times and eliminate g,f,cg,f,c.

Solution

The general circle in the plane is

x2+y2+2gx+2fy+c=0,x^2+y^2+2gx+2fy+c=0,

with three arbitrary constants g,f,cg,f,c. To eliminate them we differentiate three times, producing a third-order ODE.

Step 1 — First derivative

Differentiate once with respect to xx (treating y=y(x)y=y(x)):

2x+2yy+2g+2fy=0x+yy+g+fy=0.(1)2x+2yy'+2g+2fy'=0\quad\Longrightarrow\quad x+yy'+g+fy'=0.\tag{1}

Step 2 — Second derivative

Differentiate (1):

1+y2+yy+fy=01+y2+yy+fy=0.(2)1+y'^2+yy''+fy''=0\quad\Longrightarrow\quad 1+y'^2+yy''+fy''=0.\tag{2}

Solve for ff:

f=1+y2+yyy.f=-\frac{1+y'^2+yy''}{y''}.

Step 3 — Third derivative

Differentiate (2):

2yy+yy+yy+fy=03yy+yy+fy=0.(3)2y'y''+y'y''+yy'''+fy'''=0\quad\Longrightarrow\quad 3y'y''+yy'''+fy'''=0.\tag{3}

So f=3yy+yyyf=-\dfrac{3y'y''+yy'''}{y'''}. Equate the two expressions for ff:

1+y2+yyy=3yy+yyy.\frac{1+y'^2+yy''}{y''}=\frac{3y'y''+yy'''}{y'''}.

Step 4 — Eliminate and simplify

Cross-multiplying,

(1+y2+yy)y=(3yy+yy)y.(1+y'^2+yy'')\,y'''=(3y'y''+yy''')\,y''.

The yyyyy''y''' terms cancel on both sides:

(1+y2)y+yyy=3yy2+yyy,(1+y'^2)\,y'''+yy''y'''=3y'y''^2+yy''y''', (1+y2)y=3yy2.(1+y'^2)\,y'''=3y'\,y''^2.

Answer

  (1+y2)d3ydx3=3dydx(d2ydx2)2.  \boxed{\;(1+y'^2)\,\frac{d^3y}{dx^3}=3\,\frac{dy}{dx}\left(\frac{d^2y}{dx^2}\right)^2.\;}
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