← 2019 Paper 1
UPSC 2019 Maths Optional Paper 1 Q1c — Step-by-Step Solution
10 marks · Section A
Matrix of a linear transformation · Linear Algebra · asked 10× in 13 yrs · Read the full method →
Question
Let T:R2→R2 be a linear map such that T(2,1)=(5,7) and T(1,2)=(3,3). If A is the matrix corresponding to T with respect to the standard bases e1,e2, then find Rank (A).
Technique
Recover the standard matrix via A=[images]P−1; rank from a nonzero determinant. Faster: image of a basis is independent ⇒ full rank.
Solution
Step 1 — Set up the equation for A
Let A=[acbd] be the standard matrix of T, so T(v)=Av (columns). The data say
A[21]=[57],A[12]=[33].
Stacking these as columns,
A[2112]=[5733].
Step 2 — Solve for A
Let P=[2112], detP=4−1=3=0, so P is invertible and
P−1=31[2−1−12].
Then
A=[5733]P−1=31[5733][2−1−12]=31[10−314−3−5+6−7+6]=31[7111−1].
A=[7/311/31/3−1/3].
Step 3 — Rank of A
detA=91(7⋅(−1)−1⋅11)=9−7−11=9−18=−2=0.
A 2×2 matrix with nonzero determinant is invertible, hence of full rank.
Answer
Rank(A)=2.