← 2020 Paper 2

UPSC 2020 Maths Optional Paper 2 Q5a — Step-by-Step Solution

10 marks · Section B

Family of surfaces · PDEs · asked 7× in 13 yrs · Read the full method →

Question

Form a partial differential equation by eliminating the arbitrary functions f(x)f(x) and g(y)g(y) from z=yf(x)+xg(y)z=y\,f(x)+x\,g(y) and specify its nature (elliptic, hyperbolic or parabolic) in the region x>0, y>0x>0,\ y>0.

Technique

Eliminate two arbitrary one-variable functions by forming xp+yqxp+yq and identifying the mixed derivative ss; classify via discriminant B2ACB^2-AC of the principal part.

Solution

We have two arbitrary functions, so we expect a second-order PDE.

Step 1 — First-order partial derivatives

z=yf(x)+xg(y).z=y\,f(x)+x\,g(y). p=zx=yf(x)+g(y),q=zy=f(x)+xg(y).p=\frac{\partial z}{\partial x}=y\,f'(x)+g(y),\qquad q=\frac{\partial z}{\partial y}=f(x)+x\,g'(y).

Step 2 — A mixed second derivative

s=2zxy=f(x)+g(y).s=\frac{\partial^2 z}{\partial x\,\partial y}=f'(x)+g'(y).

Step 3 — Eliminate f,gf,g

Form the combination xp+yqx\,p+y\,q:

xp+yq=xyf(x)+xg(y)+yf(x)+xyg(y)=xy(f(x)+g(y))+(yf(x)+xg(y)).x\,p+y\,q=xy\,f'(x)+x\,g(y)+y\,f(x)+xy\,g'(y)=xy\big(f'(x)+g'(y)\big)+\big(y\,f(x)+x\,g(y)\big).

The last bracket is exactly zz, and f(x)+g(y)=sf'(x)+g'(y)=s. Hence

xp+yq=xys+z.x\,p+y\,q=xy\,s+z.

Rearranging,

  xy2zxy=xzx+yzyz  \boxed{\;xy\,\frac{\partial^2 z}{\partial x\,\partial y}=x\,\frac{\partial z}{\partial x}+y\,\frac{\partial z}{\partial y}-z\;}

This is the required PDE (all arbitrary functions eliminated).

Step 4 — Classification

Write the principal (second-order) part as

Azxx+2Bzxy+Czyy+A\,z_{xx}+2B\,z_{xy}+C\,z_{yy}+\dots

Here zxxz_{xx} and zyyz_{yy} are absent, so A=0, C=0A=0,\ C=0, and the coefficient of zxyz_{xy} is xyxy, giving 2B=xy2B=xy, i.e. B=xy2B=\tfrac{xy}{2}.

The discriminant is

B2AC=(xy2)20=x2y24.B^2-AC=\left(\frac{xy}{2}\right)^2-0=\frac{x^2y^2}{4}.

In the region x>0, y>0x>0,\ y>0 we have x2y2/4>0x^2y^2/4>0, so B2AC>0B^2-AC>0 everywhere there.

Answer

The equation is hyperbolic throughout the region x>0, y>0.\boxed{\text{The equation is \emph{hyperbolic} throughout the region } x>0,\ y>0.}
We post more of this — worked solutions, CSAT trap breakdowns, guide chapters — a few times a week on Telegram. Free, no sign-in. Join

This solution is part of the Maths Coverage Map — 13 years, mapped. Get the take-away PDF free.