← 2021 Paper 1
UPSC 2021 Maths Optional Paper 1 Q4a-i — Step-by-Step Solution
10 marks · Section A
Rank of a matrix · Linear Algebra · asked 7× in 13 yrs · Read the full method →
Question
A=102330692221426101026. Reduce to RREF; find rank.
Technique
Standard Gaussian elimination to RREF; track pivot positions; count non-zero rows.
Solution
Step 1 — Use R1 to clear column 1
R3→R3−2R1: (0,0,−2,−2,0).
R4→R4−3R1: (0,0,−5,−2,3).
1000300022−2−542−2−21003.
Step 2 — Use R2 to clear column 3
R2 has pivot in column 3 (value 2). Divide R2 by 2: (0,0,1,1,0).
R3→R3+2R2: (0,0,0,0,0).
R4→R4+5R2: (0,0,0,3,3).
R1→R1−2R2: (1,3,0,2,1).
10003000010021031003.
Step 3 — Swap R3,R4; use new R3 to clear column 4
After swap:
10003000010021301030.
Divide R3 by 3: (0,0,0,1,1).
R2→R2−R3: (0,0,1,0,−1).
R1→R1−2R3: (1,3,0,0,−1).
1000300001000010−1−110.
This is RREF.
Step 4 — Read rank
Three non-zero rows. Rank = 3.
Answer
RREF as above; rank(A)=3.