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UPSC 2014 Maths Optional Paper 1 Q1a — Step-by-Step Solution
10 marks · Section A
Subspaces · Linear Algebra · asked 6× in 13 yrs · Read the full method →
Question
Find one vector in R3 which generates the intersection of V and W, where V is the xy plane and W is the space generated by the vectors (1,2,3) and (1,−1,1).
Technique
Parametric description of W + linear constraint from V + back-substitution.
Solution
Strategy. Write a general element of W, impose the V condition (z=0), solve the resulting linear constraint.
Step 1 — Parametrise W
W={a(1,2,3)+b(1,−1,1):a,b∈R}={(a+b,2a−b,3a+b)}.
Step 2 — Intersect with V={(x,y,0)}
Require z-component =0:
3a+b=0⟹b=−3a.
Step 3 — Substitute
For any scalar a:
(a+b,2a−b,3a+b)=(a−3a,2a−(−3a),0)=(−2a,5a,0)=a(−2,5,0).
Hence V∩W=span{(−2,5,0)} — a one-dimensional subspace.
Answer
V∩W is generated by (−2,5,0).