← 2014 Paper 2

UPSC 2014 Maths Optional Paper 2 Q1e — Step-by-Step Solution

10 marks · Section A

Graphical method · Linear Programming · asked 5× in 13 yrs · Read the full method →

Question

Solve graphically: Maximize Z=6x1+5x2Z=6x_1+5x_2 subject to

2x1+x216,  x1+x211,  x1+2x26,  5x1+6x290,  x1,x20.2x_1+x_2\le 16,\;x_1+x_2\le 11,\;x_1+2x_2\ge 6,\;5x_1+6x_2\le 90,\;x_1,x_2\ge 0.

Technique

Standard 2-variable graphical LPP; enumerate vertices, check feasibility, evaluate objective.

Solution

Strategy. Identify feasible-region vertices via intersection of constraint boundaries; evaluate ZZ at each.

Step 1 — Enumerate candidate vertices

Constraint lines:

Check pairwise intersections for feasibility (all 6 constraints must hold):

PairIntersectionFeasible?
L1L2L_1\cap L_2(5,6)(5,6)✓ (all constraints check)
L1L4L_1\cap L_4(6/7,100/7)(6/7,100/7)✗ (L2L_2: 15.1>1115.1>11)
L2L4L_2\cap L_4(24,35)(-24,35)✗ (x1<0x_1<0)
L1{x2=0}L_1\cap\{x_2=0\}(8,0)(8,0)
L2{x1=0}L_2\cap\{x_1=0\}(0,11)(0,11)
L3{x2=0}L_3\cap\{x_2=0\}(6,0)(6,0)
L3{x1=0}L_3\cap\{x_1=0\}(0,3)(0,3)

Feasible vertices: (6,0),(0,3),(0,11),(5,6),(8,0)(6,0),\,(0,3),\,(0,11),\,(5,6),\,(8,0).

Step 2 — Boundary trace

Walking the feasible region counter-clockwise:

(6,0)(0,3)(0,11)(5,6)(8,0)(6,0).(6,0)\to(0,3)\to(0,11)\to(5,6)\to(8,0)\to(6,0).

The 5-gon has edges along L3L_3 (from (6,0)(6,0) to (0,3)(0,3)), x1=0x_1=0 (from (0,3)(0,3) to (0,11)(0,11)), L2L_2 (from (0,11)(0,11) to (5,6)(5,6)), L1L_1 (from (5,6)(5,6) to (8,0)(8,0)), x2=0x_2=0 (from (8,0)(8,0) to (6,0)(6,0)).

Step 3 — Evaluate ZZ at each vertex

VertexZ=6x1+5x2Z=6x_1+5x_2
(6,0)(6,0)3636
(0,3)(0,3)1515
(0,11)(0,11)5555
(5,6)(5,6)60\mathbf{60}
(8,0)(8,0)4848

Maximum: Z=60Z=60 at (x1,x2)=(5,6)(x_1,x_2)=(5,6).

Answer

  Zmax=60  at  (x1,x2)=(5,6).  \boxed{\;Z_{\max}=60\;\text{at}\;(x_1,x_2)=(5,6).\;}
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