Explain the main steps of the Gauss–Jordan method and apply this method to find the inverse of the matrix 222686668.
Technique
Gauss–Jordan elimination on [A∣I]; reduce left block to I, right block becomes A−1.
Solution
Main steps of Gauss–Jordan inversion.
Form the augmented matrix [A∣I] by appending the identity I to A.
Apply elementary row operations to reduce the left block A to the identity I (forward elimination to upper-triangular, then back-elimination, with each pivot normalised to 1).
Whatever row operations turn A into I turn I into A−1. When the left block is I, the right block is A−1, i.e. [A∣I]→[I∣A−1].
Step 1 — Augment
222686668100010001
Step 2 — Create zeros below the first pivot
R2→R2−R1 and R3→R3−R1:
2006206021−1−1010001
(The matrix is already nearly diagonal — the off-diagonals in rows 2,3 cleared at once.)
Step 3 — Eliminate the entries in row 1 above the pivots
Column 2: R1→R1−3R2 (since the (1,2) entry is 6=3⋅2):
2000206024−1−1−310001
Column 3: R1→R1−3R3 (the (1,3) entry is 6=3⋅2):