← 2018 Paper 1

UPSC 2018 Maths Optional Paper 1 Q6d — Step-by-Step Solution

12 marks · Section B

Gauss divergence theorem · Vector Analysis · asked 9× in 13 yrs · Read the full method →

Question

If SS is the surface of the sphere x2+y2+z2=a2x^2+y^2+z^2=a^2, then evaluate

S[(x+z)dydz+(y+z)dzdx+(x+y)dxdy]\iint_S\big[(x+z)\,dy\,dz+(y+z)\,dz\,dx+(x+y)\,dx\,dy\big]

using Gauss’ divergence theorem.

Technique

Recognise the flux form; F=2\nabla\cdot\vec F=2 (constant); flux =2×=2\times volume of ball =243πa3=2\cdot\frac43\pi a^3.

Solution

Step 1 — Identify the vector field

The integral is the flux SFn^dS\displaystyle\iint_S\vec F\cdot\hat n\,dS of

F=(x+z)i^+(y+z)j^+(x+y)k^,\vec F=(x+z)\,\hat i+(y+z)\,\hat j+(x+y)\,\hat k,

since dydz, dzdx, dxdydy\,dz,\ dz\,dx,\ dx\,dy are the components of n^dS\hat n\,dS.

Step 2 — Compute the divergence

F=x(x+z)+y(y+z)+z(x+y)=1+1+0=2.\nabla\cdot\vec F=\frac{\partial}{\partial x}(x+z)+\frac{\partial}{\partial y}(y+z)+\frac{\partial}{\partial z}(x+y)=1+1+0=2.

Note the third component x+yx+y has no zz-dependence, so its zz-derivative is 00 — the divergence is 22, not 33.

Step 3 — Apply Gauss’ theorem

By the divergence theorem, with VV the solid ball of radius aa (volume 43πa3\tfrac43\pi a^3):

SFn^dS=V(F)dV=V2dV=243πa3.\iint_S\vec F\cdot\hat n\,dS=\iiint_V(\nabla\cdot\vec F)\,dV=\iiint_V 2\,dV=2\cdot\frac43\pi a^3.

Answer

  S[(x+z)dydz+(y+z)dzdx+(x+y)dxdy]=83πa3.  \boxed{\;\iint_S\big[(x+z)\,dy\,dz+(y+z)\,dz\,dx+(x+y)\,dx\,dy\big]=\frac{8}{3}\pi a^3.\;}
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