← 2018 Paper 1
UPSC 2018 Maths Optional Paper 1 Q6d — Step-by-Step Solution
12 marks · Section B
Gauss divergence theorem · Vector Analysis · asked 9× in 13 yrs · Read the full method →
Question
If S is the surface of the sphere x2+y2+z2=a2, then evaluate
∬S[(x+z)dydz+(y+z)dzdx+(x+y)dxdy]
using Gauss’ divergence theorem.
Technique
Recognise the flux form; ∇⋅F=2 (constant); flux =2× volume of ball =2⋅34πa3.
Solution
Step 1 — Identify the vector field
The integral is the flux ∬SF⋅n^dS of
F=(x+z)i^+(y+z)j^+(x+y)k^,
since dydz, dzdx, dxdy are the components of n^dS.
Step 2 — Compute the divergence
∇⋅F=∂x∂(x+z)+∂y∂(y+z)+∂z∂(x+y)=1+1+0=2.
Note the third component x+y has no z-dependence, so its z-derivative is 0 — the divergence is 2, not 3.
Step 3 — Apply Gauss’ theorem
By the divergence theorem, with V the solid ball of radius a (volume 34πa3):
∬SF⋅n^dS=∭V(∇⋅F)dV=∭V2dV=2⋅34πa3.
Answer
∬S[(x+z)dydz+(y+z)dzdx+(x+y)dxdy]=38πa3.