UPSC 2020 Maths Optional Paper 1 Q7c-i — Step-by-Step Solution
10 marks · Section B
Principle of virtual work · Dynamics & Statics · asked 6× in 13 yrs · Read the full method →
Question
A square framework formed of uniform heavy rods of equal weight W jointed together, is hung up by one corner. A weight W is suspended from each of the three lower corners, and the shape of the square is preserved by a light rod along the horizontal diagonal. Find the thrust of the light rod.
Technique
Principle of virtual work with the single DOF θ (half-angle of the rods); T=(dV/dθ)/(dL/dθ).
Solution
Setup
Label the square ABCD hung from the top corner A, so the diagonal AC is vertical and the diagonal BD is horizontal. The four uniform rods AB,BC,CD,DA each have weight W. Each rod makes 45∘ with the vertical (square geometry). Hung weights W act at the three lower corners B,C,D. A light rod lies along the horizontal diagonal BD.
Use the principle of virtual work. Let each upper rod make angle θ with the downward vertical (the square configuration is θ=45∘), and let each rod have length 2a. Take A as origin, y measured upward (so the frame is at y<0).
Step 1 — Heights of all weights as functions of θ
Going down the rods at angle θ to the vertical, each rod’s vertical extent is 2acosθ.
Midpoints (CGs) of the two upper rods AB,AD: depth acosθ, i.e. y=−acosθ each.
Corners B,D: depth 2acosθ, y=−2acosθ.
Midpoints of the two lower rods BC,DC: depth 3acosθ, y=−3acosθ each.
Bottom corner C: depth 4acosθ, y=−4acosθ.
Step 2 — Total potential energy
Weights: four rod weights W at the rod midpoints, plus hung weights W at B, C, D.
Let the thrust (compressive force) in the light rod be T; it pushes the corners B and D apart, so it does positive work when LBD increases. The principle of virtual work for the single degree of freedom θ: