UPSC 2022 Maths Optional Paper 1 Q8c — Step-by-Step Solution
15 marks · Section B
Gauss divergence theorem · Vector Analysis · asked 9× in 13 yrs · Read the full method →
Question
Using Gauss’ divergence theorem, evaluate ∬SF⋅n^dS where F=x^−y^+(z2−1)k^ and S is the cylinder formed by z=0,z=1,x2+y2=4.
Technique
Gauss’ divergence: convert closed-surface flux integral to volume integral of divergence. Divergence here is 2z, integration trivial.
Solution
Setup.S is the closed surface of the cylinder: bottom disk (z=0), top disk (z=1), lateral curved surface (x2+y2=4 between z=0 and z=1). Volume V enclosed: {x2+y2≤4,0≤z≤1}.
Gauss’ theorem:∬SF⋅n^dS=∭V∇⋅FdV.
Step 1 — Divergence
∇⋅F=∂x(x)+∂y(−y)+∂z(z2−1)=1+(−1)+2z=2z.
Step 2 — Volume integral
∭V2zdV=2∫01zdz⋅∬x2+y2≤4dA=2⋅21⋅π⋅22=4π.
(Disk area =πr2=4π; ∫01zdz=1/2; factor 2 from the divergence.)